Key Concept: Frequency, Time Period
a) Frequency = 40 Hz, Time Period = 0.025 s
[Solution Description]
To find the frequency, we use the formula:
$\text{Frequency} (\nu) = \frac{\text{Number of oscillations}}{\text{Time taken}}$
Substituting the given values:
$\nu = \frac{200}{5} = 40 \, \text{Hz}$
The time period (T) is the reciprocal of frequency:
$T = \frac{1}{\nu} = \frac{1}{40} = 0.025 \, \text{s}$
Thus, the frequency is 40 Hz, and the time period is 0.025 s.
Your Answer is correct.
a) Frequency = 40 Hz, Time Period = 0.025 s
[Solution Description]
To find the frequency, we use the formula:
$\text{Frequency} (\nu) = \frac{\text{Number of oscillations}}{\text{Time taken}}$
Substituting the given values:
$\nu = \frac{200}{5} = 40 \, \text{Hz}$
The time period (T) is the reciprocal of frequency:
$T = \frac{1}{\nu} = \frac{1}{40} = 0.025 \, \text{s}$
Thus, the frequency is 40 Hz, and the time period is 0.025 s.