43. If the Sun's diameter is 100 times that of Earth and the distance from Earth to Sun is 1 au, how many times farther is Proxima Centauri compared to the Sun's diameter if its distance is 269000 au?
Key Concept: Sun's diameter, Astronomical unit, Proxima Centauri
c) $3.17 \times 10^7$ times
[Solution Description]
First, we know the Sun's diameter is 100 times the Earth's diameter. Let Earth's diameter be $D$, so Sun's diameter is $100D$.
The distance to Proxima Centauri is $269000$ au. Since 1 au is the distance from Earth to Sun ($\approx 150$ million km), we need to find how many times $269000$ au is compared to the Sun's diameter $100D$.
However, we don't have $D$ in km, but we can express the answer in terms of ratios.
So, ratio = $\frac{\text{Distance to Proxima Centauri}}{\text{Sun's diameter}} = \frac{269000 \text{ au}}{100D}$. But since 1 au $\approx 150$ million km and $D \approx 12742$ km (Earth's diameter), we can substitute:
$100D = 100 \times 12742 \text{ km} = 1274200 \text{ km}$.
Distance to Proxima Centauri = $269000 \times 150 \times 10^6 \text{ km} = 4.035 \times 10^{13} \text{ km}$.
So, ratio = $\frac{4.035 \times 10^{13}}{1.2742 \times 10^6} \approx 3.166 \times 10^7$ times.
Therefore, Proxima Centauri is about $3.17 \times 10^7$ times farther than the Sun's diameter.
Your Answer is correct.
c) $3.17 \times 10^7$ times
[Solution Description]
First, we know the Sun's diameter is 100 times the Earth's diameter. Let Earth's diameter be $D$, so Sun's diameter is $100D$.
The distance to Proxima Centauri is $269000$ au. Since 1 au is the distance from Earth to Sun ($\approx 150$ million km), we need to find how many times $269000$ au is compared to the Sun's diameter $100D$.
However, we don't have $D$ in km, but we can express the answer in terms of ratios.
So, ratio = $\frac{\text{Distance to Proxima Centauri}}{\text{Sun's diameter}} = \frac{269000 \text{ au}}{100D}$. But since 1 au $\approx 150$ million km and $D \approx 12742$ km (Earth's diameter), we can substitute:
$100D = 100 \times 12742 \text{ km} = 1274200 \text{ km}$.
Distance to Proxima Centauri = $269000 \times 150 \times 10^6 \text{ km} = 4.035 \times 10^{13} \text{ km}$.
So, ratio = $\frac{4.035 \times 10^{13}}{1.2742 \times 10^6} \approx 3.166 \times 10^7$ times.
Therefore, Proxima Centauri is about $3.17 \times 10^7$ times farther than the Sun's diameter.